R Praggnanandhaa Remains Unbeaten After Draw with Jorden van Foreest in Romania
Praggnanandhaa holds off Jorden van Foreest to stay unbeaten in Romania
The Indian Express
Image: The Indian Express
Indian chess prodigy R Praggnanandhaa drew against Dutch grandmaster Jorden van Foreest in the fourth round of the Super Chess Classic Romania 2026, maintaining his unbeaten streak in the tournament. With three draws and one win, Pragg is currently half a point behind tournament leader Vincent Keymer.
- 01Praggnanandhaa's draw with Van Foreest is his third in the tournament, alongside one victory against Javokhir Sindarov.
- 02The match against Van Foreest ended in just 35 moves, contrasting with Pragg's longer previous game.
- 03Pragg expressed satisfaction with his performance, stating, 'The tournament so far has been good except the first game.'
- 04Jorden van Foreest has risen to World No. 16 in the FIDE ratings, one spot ahead of Pragg.
- 05World championship contender Javokhir Sindarov has yet to secure a win in four rounds of the tournament.
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In the fourth round of the Super Chess Classic Romania 2026, Indian chess prodigy R Praggnanandhaa faced Dutch grandmaster Jorden van Foreest, resulting in a 35-move draw. This match marked Pragg's third draw in the tournament, alongside a notable victory against World Championship contender Javokhir Sindarov. Despite the draw, Pragg remains unbeaten and is currently half a point behind tournament leader Vincent Keymer. The game began with a Zukertort Opening but did not produce the excitement expected from such high-caliber players. After the match, Pragg reflected positively on his performance, acknowledging that while his first round was challenging, he has since played well. Meanwhile, Van Foreest's recent rise in the FIDE rankings, where he is now World No. 16, highlights his impressive comeback after a slump. Notably, Javokhir Sindarov has struggled in the tournament, failing to secure any wins in four rounds, a stark contrast to his previous form in the Candidates.
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